Integrand size = 23, antiderivative size = 83 \[ \int \frac {\tan ^6(e+f x)}{a+b \sec ^2(e+f x)} \, dx=-\frac {x}{a}+\frac {(a+b)^{5/2} \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a+b}}\right )}{a b^{5/2} f}-\frac {(a+2 b) \tan (e+f x)}{b^2 f}+\frac {\tan ^3(e+f x)}{3 b f} \]
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Time = 0.31 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.304, Rules used = {4226, 2000, 490, 596, 536, 209, 211} \[ \int \frac {\tan ^6(e+f x)}{a+b \sec ^2(e+f x)} \, dx=\frac {(a+b)^{5/2} \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a+b}}\right )}{a b^{5/2} f}-\frac {(a+2 b) \tan (e+f x)}{b^2 f}-\frac {x}{a}+\frac {\tan ^3(e+f x)}{3 b f} \]
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Rule 209
Rule 211
Rule 490
Rule 536
Rule 596
Rule 2000
Rule 4226
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {x^6}{\left (1+x^2\right ) \left (a+b \left (1+x^2\right )\right )} \, dx,x,\tan (e+f x)\right )}{f} \\ & = \frac {\text {Subst}\left (\int \frac {x^6}{\left (1+x^2\right ) \left (a+b+b x^2\right )} \, dx,x,\tan (e+f x)\right )}{f} \\ & = \frac {\tan ^3(e+f x)}{3 b f}-\frac {\text {Subst}\left (\int \frac {x^2 \left (3 (a+b)+3 (a+2 b) x^2\right )}{\left (1+x^2\right ) \left (a+b+b x^2\right )} \, dx,x,\tan (e+f x)\right )}{3 b f} \\ & = -\frac {(a+2 b) \tan (e+f x)}{b^2 f}+\frac {\tan ^3(e+f x)}{3 b f}+\frac {\text {Subst}\left (\int \frac {3 (a+b) (a+2 b)+3 \left (a^2+3 a b+3 b^2\right ) x^2}{\left (1+x^2\right ) \left (a+b+b x^2\right )} \, dx,x,\tan (e+f x)\right )}{3 b^2 f} \\ & = -\frac {(a+2 b) \tan (e+f x)}{b^2 f}+\frac {\tan ^3(e+f x)}{3 b f}-\frac {\text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\tan (e+f x)\right )}{a f}+\frac {(a+b)^3 \text {Subst}\left (\int \frac {1}{a+b+b x^2} \, dx,x,\tan (e+f x)\right )}{a b^2 f} \\ & = -\frac {x}{a}+\frac {(a+b)^{5/2} \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a+b}}\right )}{a b^{5/2} f}-\frac {(a+2 b) \tan (e+f x)}{b^2 f}+\frac {\tan ^3(e+f x)}{3 b f} \\ \end{align*}
Result contains complex when optimal does not.
Time = 3.95 (sec) , antiderivative size = 229, normalized size of antiderivative = 2.76 \[ \int \frac {\tan ^6(e+f x)}{a+b \sec ^2(e+f x)} \, dx=\frac {(a+2 b+a \cos (2 (e+f x))) \sec ^2(e+f x) \left (-\frac {3 x}{a}-\frac {3 (a+b)^{5/2} \arctan \left (\frac {\sec (f x) (\cos (2 e)-i \sin (2 e)) (-((a+2 b) \sin (f x))+a \sin (2 e+f x))}{2 \sqrt {a+b} \sqrt {b (\cos (e)-i \sin (e))^4}}\right ) (\cos (2 e)-i \sin (2 e))}{a b^2 f \sqrt {b (\cos (e)-i \sin (e))^4}}-\frac {(3 a+7 b) \sec (e) \sec (e+f x) \sin (f x)}{b^2 f}+\frac {\sec (e) \sec ^3(e+f x) \sin (f x)}{b f}+\frac {\sec ^2(e+f x) \tan (e)}{b f}\right )}{6 \left (a+b \sec ^2(e+f x)\right )} \]
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Time = 2.32 (sec) , antiderivative size = 101, normalized size of antiderivative = 1.22
method | result | size |
derivativedivides | \(\frac {-\frac {-\frac {b \tan \left (f x +e \right )^{3}}{3}+a \tan \left (f x +e \right )+2 b \tan \left (f x +e \right )}{b^{2}}+\frac {\left (a^{3}+3 a^{2} b +3 a \,b^{2}+b^{3}\right ) \arctan \left (\frac {b \tan \left (f x +e \right )}{\sqrt {\left (a +b \right ) b}}\right )}{b^{2} a \sqrt {\left (a +b \right ) b}}-\frac {\arctan \left (\tan \left (f x +e \right )\right )}{a}}{f}\) | \(101\) |
default | \(\frac {-\frac {-\frac {b \tan \left (f x +e \right )^{3}}{3}+a \tan \left (f x +e \right )+2 b \tan \left (f x +e \right )}{b^{2}}+\frac {\left (a^{3}+3 a^{2} b +3 a \,b^{2}+b^{3}\right ) \arctan \left (\frac {b \tan \left (f x +e \right )}{\sqrt {\left (a +b \right ) b}}\right )}{b^{2} a \sqrt {\left (a +b \right ) b}}-\frac {\arctan \left (\tan \left (f x +e \right )\right )}{a}}{f}\) | \(101\) |
risch | \(-\frac {x}{a}-\frac {2 i \left (3 a \,{\mathrm e}^{4 i \left (f x +e \right )}+9 b \,{\mathrm e}^{4 i \left (f x +e \right )}+6 a \,{\mathrm e}^{2 i \left (f x +e \right )}+12 b \,{\mathrm e}^{2 i \left (f x +e \right )}+3 a +7 b \right )}{3 f \,b^{2} \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right )^{3}}-\frac {\sqrt {-\left (a +b \right ) b}\, a \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \sqrt {-\left (a +b \right ) b}+a +2 b}{a}\right )}{2 b^{3} f}-\frac {\sqrt {-\left (a +b \right ) b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \sqrt {-\left (a +b \right ) b}+a +2 b}{a}\right )}{b^{2} f}-\frac {\sqrt {-\left (a +b \right ) b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \sqrt {-\left (a +b \right ) b}+a +2 b}{a}\right )}{2 b f a}+\frac {\sqrt {-\left (a +b \right ) b}\, a \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \sqrt {-\left (a +b \right ) b}-a -2 b}{a}\right )}{2 b^{3} f}+\frac {\sqrt {-\left (a +b \right ) b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \sqrt {-\left (a +b \right ) b}-a -2 b}{a}\right )}{b^{2} f}+\frac {\sqrt {-\left (a +b \right ) b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \sqrt {-\left (a +b \right ) b}-a -2 b}{a}\right )}{2 b f a}\) | \(383\) |
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Leaf count of result is larger than twice the leaf count of optimal. 148 vs. \(2 (73) = 146\).
Time = 0.31 (sec) , antiderivative size = 373, normalized size of antiderivative = 4.49 \[ \int \frac {\tan ^6(e+f x)}{a+b \sec ^2(e+f x)} \, dx=\left [-\frac {12 \, b^{2} f x \cos \left (f x + e\right )^{3} - 3 \, {\left (a^{2} + 2 \, a b + b^{2}\right )} \sqrt {-\frac {a + b}{b}} \cos \left (f x + e\right )^{3} \log \left (\frac {{\left (a^{2} + 8 \, a b + 8 \, b^{2}\right )} \cos \left (f x + e\right )^{4} - 2 \, {\left (3 \, a b + 4 \, b^{2}\right )} \cos \left (f x + e\right )^{2} - 4 \, {\left ({\left (a b + 2 \, b^{2}\right )} \cos \left (f x + e\right )^{3} - b^{2} \cos \left (f x + e\right )\right )} \sqrt {-\frac {a + b}{b}} \sin \left (f x + e\right ) + b^{2}}{a^{2} \cos \left (f x + e\right )^{4} + 2 \, a b \cos \left (f x + e\right )^{2} + b^{2}}\right ) + 4 \, {\left ({\left (3 \, a^{2} + 7 \, a b\right )} \cos \left (f x + e\right )^{2} - a b\right )} \sin \left (f x + e\right )}{12 \, a b^{2} f \cos \left (f x + e\right )^{3}}, -\frac {6 \, b^{2} f x \cos \left (f x + e\right )^{3} + 3 \, {\left (a^{2} + 2 \, a b + b^{2}\right )} \sqrt {\frac {a + b}{b}} \arctan \left (\frac {{\left ({\left (a + 2 \, b\right )} \cos \left (f x + e\right )^{2} - b\right )} \sqrt {\frac {a + b}{b}}}{2 \, {\left (a + b\right )} \cos \left (f x + e\right ) \sin \left (f x + e\right )}\right ) \cos \left (f x + e\right )^{3} + 2 \, {\left ({\left (3 \, a^{2} + 7 \, a b\right )} \cos \left (f x + e\right )^{2} - a b\right )} \sin \left (f x + e\right )}{6 \, a b^{2} f \cos \left (f x + e\right )^{3}}\right ] \]
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\[ \int \frac {\tan ^6(e+f x)}{a+b \sec ^2(e+f x)} \, dx=\int \frac {\tan ^{6}{\left (e + f x \right )}}{a + b \sec ^{2}{\left (e + f x \right )}}\, dx \]
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Time = 0.27 (sec) , antiderivative size = 95, normalized size of antiderivative = 1.14 \[ \int \frac {\tan ^6(e+f x)}{a+b \sec ^2(e+f x)} \, dx=-\frac {\frac {3 \, {\left (f x + e\right )}}{a} - \frac {b \tan \left (f x + e\right )^{3} - 3 \, {\left (a + 2 \, b\right )} \tan \left (f x + e\right )}{b^{2}} - \frac {3 \, {\left (a^{3} + 3 \, a^{2} b + 3 \, a b^{2} + b^{3}\right )} \arctan \left (\frac {b \tan \left (f x + e\right )}{\sqrt {{\left (a + b\right )} b}}\right )}{\sqrt {{\left (a + b\right )} b} a b^{2}}}{3 \, f} \]
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Time = 2.09 (sec) , antiderivative size = 126, normalized size of antiderivative = 1.52 \[ \int \frac {\tan ^6(e+f x)}{a+b \sec ^2(e+f x)} \, dx=-\frac {\frac {3 \, {\left (f x + e\right )}}{a} - \frac {3 \, {\left (a^{3} + 3 \, a^{2} b + 3 \, a b^{2} + b^{3}\right )} {\left (\pi \left \lfloor \frac {f x + e}{\pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (b\right ) + \arctan \left (\frac {b \tan \left (f x + e\right )}{\sqrt {a b + b^{2}}}\right )\right )}}{\sqrt {a b + b^{2}} a b^{2}} - \frac {b^{2} \tan \left (f x + e\right )^{3} - 3 \, a b \tan \left (f x + e\right ) - 6 \, b^{2} \tan \left (f x + e\right )}{b^{3}}}{3 \, f} \]
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Time = 19.88 (sec) , antiderivative size = 1109, normalized size of antiderivative = 13.36 \[ \int \frac {\tan ^6(e+f x)}{a+b \sec ^2(e+f x)} \, dx=\frac {{\mathrm {tan}\left (e+f\,x\right )}^3}{3\,b\,f}-\frac {\mathrm {atan}\left (\frac {40\,a^2\,\mathrm {tan}\left (e+f\,x\right )}{30\,a\,b+40\,a^2+10\,b^2+\frac {30\,a^3}{b}+\frac {12\,a^4}{b^2}+\frac {2\,a^5}{b^3}}+\frac {30\,a^3\,\mathrm {tan}\left (e+f\,x\right )}{30\,a\,b^2+40\,a^2\,b+30\,a^3+10\,b^3+\frac {12\,a^4}{b}+\frac {2\,a^5}{b^2}}+\frac {12\,a^4\,\mathrm {tan}\left (e+f\,x\right )}{30\,a\,b^3+30\,a^3\,b+12\,a^4+10\,b^4+40\,a^2\,b^2+\frac {2\,a^5}{b}}+\frac {2\,a^5\,\mathrm {tan}\left (e+f\,x\right )}{2\,a^5+12\,a^4\,b+30\,a^3\,b^2+40\,a^2\,b^3+30\,a\,b^4+10\,b^5}+\frac {10\,b^2\,\mathrm {tan}\left (e+f\,x\right )}{30\,a\,b+40\,a^2+10\,b^2+\frac {30\,a^3}{b}+\frac {12\,a^4}{b^2}+\frac {2\,a^5}{b^3}}+\frac {30\,a\,b\,\mathrm {tan}\left (e+f\,x\right )}{30\,a\,b+40\,a^2+10\,b^2+\frac {30\,a^3}{b}+\frac {12\,a^4}{b^2}+\frac {2\,a^5}{b^3}}\right )}{a\,f}-\frac {\mathrm {tan}\left (e+f\,x\right )\,\left (a+2\,b\right )}{b^2\,f}-\frac {\mathrm {atan}\left (\frac {\frac {\sqrt {-b^5\,{\left (a+b\right )}^5}\,\left (\frac {2\,\mathrm {tan}\left (e+f\,x\right )\,\left (a^6+6\,a^5\,b+15\,a^4\,b^2+20\,a^3\,b^3+15\,a^2\,b^4+6\,a\,b^5+2\,b^6\right )}{b^3}+\frac {\sqrt {-b^5\,{\left (a+b\right )}^5}\,\left (\frac {4\,a^4\,b^3+12\,a^3\,b^4+8\,a^2\,b^5}{b^3}+\frac {\mathrm {tan}\left (e+f\,x\right )\,\left (4\,a^3\,b^5+8\,a^2\,b^6\right )\,\sqrt {-b^5\,{\left (a+b\right )}^5}}{a\,b^8}\right )}{2\,a\,b^5}\right )\,1{}\mathrm {i}}{2\,a\,b^5}+\frac {\sqrt {-b^5\,{\left (a+b\right )}^5}\,\left (\frac {2\,\mathrm {tan}\left (e+f\,x\right )\,\left (a^6+6\,a^5\,b+15\,a^4\,b^2+20\,a^3\,b^3+15\,a^2\,b^4+6\,a\,b^5+2\,b^6\right )}{b^3}-\frac {\sqrt {-b^5\,{\left (a+b\right )}^5}\,\left (\frac {4\,a^4\,b^3+12\,a^3\,b^4+8\,a^2\,b^5}{b^3}-\frac {\mathrm {tan}\left (e+f\,x\right )\,\left (4\,a^3\,b^5+8\,a^2\,b^6\right )\,\sqrt {-b^5\,{\left (a+b\right )}^5}}{a\,b^8}\right )}{2\,a\,b^5}\right )\,1{}\mathrm {i}}{2\,a\,b^5}}{\frac {2\,\left (a^5+6\,a^4\,b+15\,a^3\,b^2+19\,a^2\,b^3+12\,a\,b^4+3\,b^5\right )}{b^3}-\frac {\sqrt {-b^5\,{\left (a+b\right )}^5}\,\left (\frac {2\,\mathrm {tan}\left (e+f\,x\right )\,\left (a^6+6\,a^5\,b+15\,a^4\,b^2+20\,a^3\,b^3+15\,a^2\,b^4+6\,a\,b^5+2\,b^6\right )}{b^3}+\frac {\sqrt {-b^5\,{\left (a+b\right )}^5}\,\left (\frac {4\,a^4\,b^3+12\,a^3\,b^4+8\,a^2\,b^5}{b^3}+\frac {\mathrm {tan}\left (e+f\,x\right )\,\left (4\,a^3\,b^5+8\,a^2\,b^6\right )\,\sqrt {-b^5\,{\left (a+b\right )}^5}}{a\,b^8}\right )}{2\,a\,b^5}\right )}{2\,a\,b^5}+\frac {\sqrt {-b^5\,{\left (a+b\right )}^5}\,\left (\frac {2\,\mathrm {tan}\left (e+f\,x\right )\,\left (a^6+6\,a^5\,b+15\,a^4\,b^2+20\,a^3\,b^3+15\,a^2\,b^4+6\,a\,b^5+2\,b^6\right )}{b^3}-\frac {\sqrt {-b^5\,{\left (a+b\right )}^5}\,\left (\frac {4\,a^4\,b^3+12\,a^3\,b^4+8\,a^2\,b^5}{b^3}-\frac {\mathrm {tan}\left (e+f\,x\right )\,\left (4\,a^3\,b^5+8\,a^2\,b^6\right )\,\sqrt {-b^5\,{\left (a+b\right )}^5}}{a\,b^8}\right )}{2\,a\,b^5}\right )}{2\,a\,b^5}}\right )\,\sqrt {-b^5\,{\left (a+b\right )}^5}\,1{}\mathrm {i}}{a\,b^5\,f} \]
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